Finishing up the Coordinate Geometry Unit

The rest of the unit will be done with worksheets so the homework every night is to finish the worksheet started in class.

11/26  Recap of coordinate work so far
11/27  Coordinate Proofs - Day 1 (numerical proofs)
11/28  Coordinate Proofs - Day 2 (general proofs)
11/29  Coordinate Proofs - Day 3 (mix of numerical and general proofs)

12/03  Review of Unit (answer key)
12/04  Individual Assessment (A-Block)
12/05  Group Assessment (A-Block)  Individual Assessment (F-Block)
12/06  Group Assessment (F-Block)  start the next section (A-Block)

After this we will be going on to transformations from a geometric perspective (putting together the transformations of functions with the coordinate work that we have been doing).

Excellent description from quiz

I am going to post excellent responses to the question of the relationship between the Distance Formula, the Pythagorean Theorem and the Equation of a Circle:

"The Distance Formula is actually the Pythagorean Theorem unsquared.  Instead of d^2 (c^2) it's just d and (x1-x2)^2 and (y1-y2)^2 are a^2 and b^2.  The equation of a circle is the Pythagorean Theorem.  (x - h)^2 is a^2 and (y - k)^2 is b^2, while the radius  squared is c^2."

"They are all in some way forms of the Pythagorean Theorem, and they can all be used to find the distance between two points on a graph."

"They all tell the distance of something.  The Distance formula tells the distance of point A to point B.  The Pythagorean theorem tells the length or distance of side C. And the equation of a circle calculates the distance of points from the center of the circle."

Good one for the the Pythagorean Theorem - Distance formula link:
"The distance formula is related to the Pythagorean Theorem because they both find distance.  The distance formula uses coordinates and the Pythagorean Theorem uses already known lengths, which can all be found by using coordinates."

Good one for the Distance Formula - Circle Equation link:
The equation of a circle is the distance formula, just after squaring both sides to make it d^2 = (x1-x2)^2 + (y1-y2)^2.  This is because when you are graphing a circle, the point it is centered around, or (h, k), is the same as (x2, y2).  Also, the radius (r^2) is just the distance from the center of the circle to any point on the circle.

And best of all...

"The distance formula is like the pythagorean theorem because finding the distance between two points is the same as finding the hypotenuse of a triangle if the two points were the legs of the triangle.  It is related to the equation of a circle because in a circle you are finding points at a certain distance away from the middle."

Think about your answer.  How does it compare for completeness and clarity?

Beginning Coordinate Geometry

Our next section of this unit is on coordinate geometry.  Much of this material would have been covered last year if you had take Math 1 so we are using copies of some sections from the Math 1 book.

11/08  Post-Quiz do "Getting Started" in 8C, p.659-661/1-11
11/09  Midpoint (and Distance) Formula (F-Block)
           CW p.662-663 In-Class Experiment, p.666/1,2,5,6,  HW p.667-668/7-14, 16-22

11/12  Veterans' Day - no school
11/13  Midpoint (and Distance) Formula (A-Block)

           CW p.662-663 In-Class Experiment, p.666/1,2,5,6,  HW p.667-668/7-14, 16-22

11/14  Parallel Lines and Collinear Points

           CW p.669 In-Class Experiment, p.671 For You to Do;  HW p.672-673/1-7, 9

11/15  Perpendicular Lines

           CW Handout of Exploration  HW p.677-678/1-3, 5-8, 10-12

11/16  Circles, Secants and Tangents  (F-Block)

           CW/HW handout

11/19  Circles, Secants and Tangents (A-Block),  Locus Problems (F-Block)

           CW/HW handout

11/20  Locus Problems (A-Block)

           CW/HW handout

11/21  Follow-up locus problem  (Half Day A C F H)
11/22  Thanksgiving!